{d4}.{02} = 1101 0100 << 1 (<< is left shift, 1 is the number of shift done, pad on with 0's) = 1010 1000 XOR 0001 1011 (because the leftmost is a 1 before shift) ans = 1011 0011 now what about : {5d}.{02} witch 5d=01011101 here the lift most is not (1) .. how it's done ??
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